Explorar o código

修复embed range表单name属性错误问题

jqh %!s(int64=4) %!d(string=hai) anos
pai
achega
587838b7c2
Modificáronse 1 ficheiros con 1 adicións e 1 borrados
  1. 1 1
      src/Form/EmbeddedForm.php

+ 1 - 1
src/Form/EmbeddedForm.php

@@ -247,7 +247,7 @@ class EmbeddedForm
 
         if (is_array($jsonKey)) {
             foreach ($jsonKey as $index => $name) {
-                $elementName[$index] = $this->formatName("{$this->column}").$name;
+                $elementName[$index] = $this->formatName("{$this->column}.{$name}");
                 $errorKey[$index] = "{$this->column}.$name";
                 $elementClass[$index] = $this->formatClass("{$this->column}_$name");
             }